x^2+20x-3750=0

Solution for x^2+20x-3750=0 equation:

x^2+20x-3750=0

a = 1; b = 20; c = -3750;
Δ = b2-4ac
Δ = 202-4·1·(-3750)
Δ = 15400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15400}=\sqrt{100*154}=\sqrt{100}*\sqrt{154}=10\sqrt{154}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{154}}{2*1}=\frac{-20-10\sqrt{154}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{154}}{2*1}=\frac{-20+10\sqrt{154}}{2}
$